7[z-(5z+18)+2]=3(z+4)

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Solution for 7[z-(5z+18)+2]=3(z+4) equation:


Simplifying
7[z + -1(5z + 18) + 2] = 3(z + 4)

Reorder the terms:
7[z + -1(18 + 5z) + 2] = 3(z + 4)
7[z + (18 * -1 + 5z * -1) + 2] = 3(z + 4)
7[z + (-18 + -5z) + 2] = 3(z + 4)

Reorder the terms:
7[-18 + 2 + z + -5z] = 3(z + 4)

Combine like terms: -18 + 2 = -16
7[-16 + z + -5z] = 3(z + 4)

Combine like terms: z + -5z = -4z
7[-16 + -4z] = 3(z + 4)
[-16 * 7 + -4z * 7] = 3(z + 4)
[-112 + -28z] = 3(z + 4)

Reorder the terms:
-112 + -28z = 3(4 + z)
-112 + -28z = (4 * 3 + z * 3)
-112 + -28z = (12 + 3z)

Solving
-112 + -28z = 12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-112 + -28z + -3z = 12 + 3z + -3z

Combine like terms: -28z + -3z = -31z
-112 + -31z = 12 + 3z + -3z

Combine like terms: 3z + -3z = 0
-112 + -31z = 12 + 0
-112 + -31z = 12

Add '112' to each side of the equation.
-112 + 112 + -31z = 12 + 112

Combine like terms: -112 + 112 = 0
0 + -31z = 12 + 112
-31z = 12 + 112

Combine like terms: 12 + 112 = 124
-31z = 124

Divide each side by '-31'.
z = -4

Simplifying
z = -4

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